$I_{rms}= 4.314 AExplanation:According to the definition of the root mean square value of current, the value of direct current which passes through the same circuit in which an alternating current is passing and producing same amount of heat as the direct current produced is called root mean square value of current. So, the relation between the root mean square value of current and the peak value of alternating current is given by [tex]I_{rms}=\frac{I_{0}}{\sqrt{2}}$

$I_{rms}=\frac{6.1}}{\sqrt{2}}$

[tex]I_{rms}= 4.314 A

6 0

3 years ago

A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2 m v₀²

v = √2 v₀

6 0

3 years ago