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3 years ago

Write the equation of the quadratic function with roots 0 and 2 and a vertex at (1,5).

Mathematics

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

Step-by-step explanation:

y=a(x-0)(x-2)

=a(x^2-2x)

=a(x^2-2x+1-1)

or y=a(x-1)^2-a

(1,5) lies on it.

5=a(1-1)^2-a

5=0-a

or a=-5

so y=-5(x-1)^2+5

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Is it possible to split a jackpot of $2,783,000 equally among 9 winners? Explain your answer.

Katena32 [7]

Answer:

No it isnt possible

Step-by-step explanation:

it is not because 2,783,000 is not divisible by 9

4 0

2 years ago

In Exercises 51−56, the letters a, b, and c represent nonzero constants. Solve the equation for x

Nonamiya [84]

Answer:

x = -8/b

Step-by-step explanation:

2bx – bx = -8

Combine like terms

bx = -8

Divide by b

bx/b = -8/b

x = -8/b

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3 years ago

I need help :/ i have five questions

IrinaK [193]

Answer:

Step-by-step explanation:

1. The given equation is:

$\frac{3}{5}{\times}\frac{4}{5}$

Multiplying both the terms, we get

$\frac{12}{25}$

Option A is correct.

2. The given equation is:

$2\frac{1}{3}{\times}\frac{3}{4}$

Converting the improper fraction into the mixed fraction,

$\frac{7}{3}{\times}\frac{3}{4}$

= $\frac{7}{4}$

Option C is correct.

3. The given equation is:

$\frac{3}{16}{\times}\frac{4}{21}$

Multiplying both the terms, we get

= $\frac{1}{28}$

4. The given equation is:

$3\frac{8}{9}{\times}4\frac{4}{5}$

Converting the improper fraction into the mixed fraction,

$\frac{35}{9}{\times}\frac{24}{5}$

= $\frac{56}{3}$

5. One package contains= $5\frac{1}{4}=\frac{21}{4}$ pounds of raisins.

$4\frac{2}{3}$ packages contains= $4\frac{2}{3}{\times}5\frac{1}{4}$ pounds of raisins.

= $\frac{14}{3}{\times}\frac{21}{4}$

= $\frac{49}{2}$

Therefore, the baker used $\frac{49}{2}$ pounds of raisins.

5 0

4 years ago

Help please i need this done soon!! tysm!!

olga nikolaevna [1]

Answer:

Step-by-step explanation:

Opposite Angles are supplementary in cyclic quadratlerials.

3 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago