The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean,
= 90 wpm
The standard deviation of the population ,
= 10
Sample size, n = 12
Sample mean,
= 95
The reading rate of students follows the normal distribution.
Let z = 
= 
= 1.732
Probability that the mean reading exceeds 95 wpm = P(
>95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
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Because she used the AC
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It is $105 more in August than in October.
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Step-by-step explanation:
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5 different ways
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for the 8
2 and 6
3 and 5
4 and 4
for then tens
5 and 5
4 and 6
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1. (27) 2. (1) 3.(there isn't a mode, all values appeared only once.)
Step-by-step explanation: