Question

Plz help me solve this algebra

Answer 1

Answer:

$x=5, \\x=-1$

Step-by-step explanation:

Given $(x-2)^2=9$, to solve for $x$, our goal is to isolate $x$.

Take the square root of both sides:

$x-2=\pm\sqrt{9},\\x-2=\pm 3$(recall that $3^2=(-3)^2=9$).

Therefore, we have two cases:

$\begin{cases}x-2=3,x=\boxed{5} \\x-2=-3, x=\boxed{-1}\end{cases}$