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WITCHER [35]
3 years ago
15

If an atom has a radius of 65pm, what is its circumference

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0
To calculate circumference, you must use the equation (65)(2)(Pi) which would be 408.2pm. (IF YOU COUNT PI AS 3.14)
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If I jogged for 1/3 of an hour and then walked for 1/4 of an hour. How many minutes did I exercise? What fraction of an hour did
Over [174]

Answer:

7/12 of an hour or 35 minutes

Step-by-step explanation:

5 0
2 years ago
The ratio of students with brown eyes in Michelle’s class to all of the students in her class is 20:25. What is another way to w
harina [27]

Answer:

3/4, 5/6, 8/10 this is in fraction form though. just change it to 3:4

8 0
3 years ago
Can anybody answer this correctly thank you
Ghella [55]

its the second one....

4 0
3 years ago
Sandra is a real estate agent and rams 5000 commission on the selling of a 62,000 house. what is the percent of commission she r
sveta [45]
To find a percent, you use this simple formula:
5000/62000 = x/100

In this case, x is going to be your percent of commission.

So, to find this, you first divide 5000 by 62000, which is about equal to 0.08.

Now your equation looks like this:
0.08 = x/100

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8 0
2 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
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