What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
x+6.3
Step-by-step explanation:
x+6.3
If my answer is incorrect, pls correct me!
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Answer:
48.
Step-by-step explanation:
To find the missing number write out the equation :
67 + 65 + ? = 180.
67 + 65 = 132
To find out how much more we need you can minus 132 from 180.
180 - 132 = 48.
Plug it in to see if it works.
67 + 65 + 48 does equal 180.
Hope this helps,
Davinia.
Answer:
54
Step-by-step explanation:
You have to do the number of options in each category by itsself