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yawa3891 [41]
3 years ago
14

You are offered an item for $13.79. If the seller states he normally sells the same item for $14.95, what percentage discount is

he offering you?
Mathematics
2 answers:
Aloiza [94]3 years ago
8 0
8% discount. 

Take 13.79 divided by 14.95 and the answer is . 92, meaning that 13.79 is 92% of 14.95. Then you need to take .92 from 1.00, resulting in .08, which is the discount. 

Alexxx [7]3 years ago
6 0
What i did was $13.79-$14.95 and got $-1.16 hope this helps you figure out your answer

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<u>5%</u>

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Re-write the quadratic function below in Standard Form<br> y = -(x – 3)2 +8
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Answer:

y = -x² + 6x - 1

General Formulas and Concepts:

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define equation</u>

y = -(x - 3)² + 8

<u>Step 2: Rewrite</u>

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4 0
3 years ago
Evaluate the expression if m = 3.<br><br> 3m^2<br><br><br> (SHOW YOUR WORK)
iragen [17]

The value of given expression when m = 3 is 27

<h3><u>Solution:</u></h3>

Given expression is 3m^2

We have to evaluate the given expression for m = 3

To find for m is equal to 3, substitute m = 3 in given expression

From given expression,

\rightarrow 3m^2

Plug in m = 3 in above expression

\rightarrow 3(3)^2 ------ eqn 1

We know that,

a^2 can be expanded as,

a^2=a \times a

Applying this in eqn 1, we get

\rightarrow 3(3)^2=3 \times (3 \times 3)

Simplify the above expression

\rightarrow 3(3)^2=3 \times (3 \times 3) = 3 \times 9 = 27

Therefore, for m = 3 we get,

\rightarrow 3(3)^2=27

Thus value of given expression when m = 3 is found

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3 years ago
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Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
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Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
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Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
Read 2 more answers
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