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yawa3891 [41]
3 years ago
14

You are offered an item for $13.79. If the seller states he normally sells the same item for $14.95, what percentage discount is

he offering you?
Mathematics
2 answers:
Aloiza [94]3 years ago
8 0
8% discount. 

Take 13.79 divided by 14.95 and the answer is . 92, meaning that 13.79 is 92% of 14.95. Then you need to take .92 from 1.00, resulting in .08, which is the discount. 

Alexxx [7]3 years ago
6 0
What i did was $13.79-$14.95 and got $-1.16 hope this helps you figure out your answer

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Makovka662 [10]
4 a⁴ - 2 b² + 40 :

4 * ( 2⁴) - 2  * ( 7²)  + 40 = 

4 * 16 - 2 * 49 + 40 =

64 - 98 + 40 =

-34 + 40 =

+ 6

<span>hope this helps!</span>
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3 years ago
F(x)=x^2+5x what are the real zeroes of this function?
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What is the distance between two points(2,-6)(-7,1)
Ilia_Sergeevich [38]

Answer:

11.4

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3 0
3 years ago
Read 2 more answers
Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

8 0
3 years ago
I need help please thank you
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