Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
1/4 divided by 5 is 0.05 or 1/20
Answer:
305
Step-by-step explanation:
We are adding 3 each time
5+3 = 8
8+3 = 11
The formula for an arithmetic sequence is
an = a1+d(n-1) where a1 is the first term and d is the common difference
an = 5+3(n-1)
We want the 101 term
a101 = 5 +3(101-1)
= 5+3(100)
= 5+300
= 305
