Use cross multiplication. 42 inches is your 100%. your fraction would be 42/100
then, to find by what percent it has increased, since 47 is your new height, and you are trying to find the percentage for that, the fraction will be 47/X.
42 47
----- -----
100 X
(100 * 47) / 42 = X
100 multiplied by 47, then divided by 42, the result is X
your answer should be 111%. Subtract 100 from 111, to get the increased percent.
Answer: 11%
I did this last year, so it may be a little rusty. If im wrong, hopefully someone will correct me, if not, im pretty sure this looks rights. Your methods may also be different. i use cross mulitplication
Step-by-step explanation:
the slope of the line between the first 2 points must be the same as the slope between the second and the third point.
the slope is y difference / x difference.
so,
b/a = d/c
-3/1.6 = d/1.5
d = -3×1.5 / 1.6 = -4.5 / 1.6 = -2.8125
Answer:
Step-by-step explanation:
The base is 6.
In order to find this, we can set the legs equal to each other since legs have the same length in an isosceles triangle.
x + 1 = -x + 7
2x + 1 = 7
2x = 6
x = 3
Now that we have the value for x, we can plug into the equation to get the value for the base.
3x - 3 = base
3(3) - 3 = base
9 - 3 = base
6 = base
Answer:
This is an exponential growth equation of the form:
f(t) = A*(r)^t
Where:
A is the initial quantity of something, suppose that is the population of some kind of animal
r is the rate of growth
t is the variable, usually represents a unit of time.
f(t) is the population of the animal at the time t.
For this question, we have the equation:
b(t) = 1200*(1.8)^t
And this represents the population of a kind of bacteria as a function of time.
a) 1200 is the initial population of the bacteria.
b) the 1.8 is the rate of growth.
c) Now we have the equation:
b(t) = 1000*(1.8)^t
In this case, 1000 will represent the initial population of bacteria for this second study.
And the difference between the 1200 for the first study, and the 1000 for this second study, means that for the first study the initial population of bacteria was larger. (200 units larger).
