Question

10(5 - n) - 1 = 29 n = ? Help!

Answer 1

To get rid of the parantheses we must multiply 10 by anything inside the parantheses.

10(5-n)-1=29

50-10n-1=29

Combine like terms

50-10n-1=29

49-10n=29

Subtract 49 from both sides

49-10n=29

-10n=-20

Divide both sides by -10

-10n/-10=-20/-10

n=2

Our final answer is 2

Hope this helps!

Answer 2

n = 2

distribute and simplify left side of equation

50 - 10n - 1 = 29

49 - 10n = 29 ( subtract 49 from both sides )

- 10n = 29 - 49 = - 20

n = $\frac{-20}{-10}$ = 2