Answer:
8% increase
Step-by-step explanation:
In this question, we are asked to calculate the percentage increase that a certain increment will give over a period of 10 years.
Let the increment be x
Mathematically from the question, we can obtain that ;
(1+x)^10 = (1+1.2)
(1+x)^10 = 2.2
1+ x = 2.2^1/10
1+x = 1.082
x = 1.082 - 1
x = 0.082
This means that x = 8.2% which is approximately 8%
x = amount of 21% alloy
y = amount of 50% alloy
The metallurgist wants a combination weighing a total of 44 lb, so
x + y = 44
Each pound of either alloy contributes either 0.21 or 0.5 pound of titanium. The final product needs to be comprised of 37% titanium; weighing at 44 lb, this means it should contain 0.37 * 44 = 16.28 lb. So
0.21x + 0.5y = 16.28
From the first equation,
x + y = 44 ==> y = 44 - x
Substitute this into the second equation and solve for x:
0.21x + 0.5(44 - x) = 16.28
-0.29x = -5.72 ==> x = 19.72
Substitute this into the first equation to solve for y:
19.72 + y = 44 ==> y = 24.28
Hello,
Answer A
Let's the width of the rectangle
2a-5 its length
Teh half perimeter is 80/2=40
a+2a-5=40 ==>3a=45==>a=15 and 2a-5=30-5=25
16 mph is the answer I found after doing the work
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
