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Misha Larkins [42]
3 years ago
12

(3x + 5y +1) + (5x + y-2)=?​

Mathematics
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

8x+6y+(-1)

Step-by-step explanation:

3x+5x=8x  5y+y=6y  1-2=(-1)   Add it all together

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A rectangular brick has a length of 5 centimeters, a width of 9 centimeters and a height of 20 centimeters.What is the surface a
a_sh-v [17]
ANSWER
The surface area of the brick is;

650 \: {cm}^{2}

EXPLANATION

The dimensions of the rectangular brick are

l = 5cm
w = 9cm
h = 20cm

The total surface area of a rectangular brick is given by,

T.S.A = 2(lw + lh + hw)

We substitute the values into the formula to obtain,

T.S.A = 2(5 \times 9 + 5 \times 20 + 9 \times 20)

T.S.A = 2(45+ 100+ 180)

T.S.A = 2(325)

T.S.A =650 \: {cm}^{2}
6 0
3 years ago
What is the value of the expression shown below?
stiv31 [10]
6 +(9 -1)²/4×(1/2)⁴
= 6 +8²/4×(1/2)⁴ . . . . . . evaluate parentheses
= 6 +64/4×(1/16) . . . . . . evaluate exponents
= 6 +16×(1/16) . . . . . . . . perform multiplication and divison left to right
= 6 +1
= 7
4 0
4 years ago
7m - 3m-6 < 6 help pls​
fenix001 [56]

Answer:

m < 3

Step-by-step explanation:

7m-3m - 6 < 6

4m < 6 + 6

4m < 12

4m ÷ 4 < 12 ÷ 4

m < 3

6 0
3 years ago
The length of a rectangle is 5 inches more than 3 times the width. If the area of the rectangle is 68 square inches, what is the
Paladinen [302]

Answer:

Width=4, and Length=17

Step-by-step explanation:

first you will make a variable for the width which i will say is x

now make it an equation (3x+5) (x) = 68

then solve 3x^2+5x=68

then 3x^2+5x-68=0

then x=4

then you have to substitute so 3(4)+5= 17 and 4

6 0
3 years ago
This has to do with mean,median,mode, and all that stuff, but my teacher is like,not really good at explaining stuff lol
Flura [38]

The average of 6 quiz scores, where x is the score of the last quiz, is

\dfrac{83+81+89+92+80+x}6=\dfrac{425+x}6

The student needs a minimum average of 86 to earn an A:

\dfrac{425+x}6=86\implies425+x=516\implies x=91

so the student needs a score of 91.

5 0
3 years ago
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