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olasank [31]
3 years ago
10

Please help, i’ll give brainiest answer :) [Image]

Mathematics
1 answer:
anygoal [31]3 years ago
5 0

Answer: 20

<u>Step-by-step explanation:</u>

  • Step 1: Find the vertices (intersections) of the constraints by either graphing or solving the system of equations. I graphed them and found two of the vertices: (0, 1) and (4,0) but needed to solve the system to find the third vertex (point of intersection).

-x + 3 = \frac{1}{3}x + 1

<u>+x   -1 </u>   <u>   +x  -1 </u>

      2 = \frac{4}{3}x

  (3)2 = (3)\frac{4}{3}x

      6 = 4x

  <u>  ÷4 </u>   <u>÷4 </u>

     \frac{3}{2} =  x

y = \frac{1}{3}x + 1

  = \frac{1}{3}(\frac{3}{2)} + 1

  =  \frac{1}{2} + 1

   = \frac{3}{2}x

Third vertex is at (\frac{3}{2},\frac{3}{2)}

  • Step 2: Input the vertices into the objective function: C = 5x - 4y

(0, 1): C = 5(0) - 4(1)

            =   0   -  4

            =      -4

(\frac{3}{2},\frac{3}{2)}: C = 5(\frac{3}{2}) - 4(\frac{3}{2})

            = \frac{15}{2} - \frac{12}{2}

            =      \frac{3}{2}

            =      1.5

(4, 0): C = 5(4) - 4(0)

            =  20   -  0

            =      20

  • Step 3: Evaluate the answers above to find the maximum: <em>20</em>

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