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Helen [10]
3 years ago
13

By what percent must we decrease the number A to obtain the number 4A/5?

Mathematics
1 answer:
Schach [20]3 years ago
8 0

\bf \cfrac{4A}{5}\implies \cfrac{4}{5}\cdot A\impliedby \textit{A is being reduced to four fifths} \\\\\\ \stackrel{\textit{let's convert four fifths to percentage}}{\cfrac{4}{5}\cdot 100\implies \cfrac{400}{5}\implies 80}


so 4/5 of A is really 80% of A then.

since a whole A is 100% of A, 100% - 80% = 20%, A is being reduced by 20%, namely 1/5.

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What equation shows 10x-2y=10 in slope intercept form
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10x-2y=10
-2y = -10x +10 Subtracted 10x from both sides
y = 5x - 5 Divided both sides by -2

y = 5x - 5 Is slope intercept form
5 0
3 years ago
Given the following Venn diagram:<br><br> Find M N.
aliina [53]
If you want the intersect of M and N, then:

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3 0
3 years ago
Read 2 more answers
Can you explain how to do 13 please
Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
3 0
3 years ago
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Gennadij [26K]

Answer: <B is congruent to <E

Step-by-step explanation:

There is no “angle,angle,angle” theorem when proving triangles are congruent.

There are 5 however that do:

ASA (angle, included side, angle)

SSS (side, side, side)

SAS (side, included angle, side)

AAS (angle,angle, non included side)

HL (hypotenuse,leg)

6 0
2 years ago
12 cm long 10 cm wide area square meters
Stels [109]

Answer:

120 sqcm, is the answer

6 0
2 years ago
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