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Brut [27]
3 years ago
12

Please help

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0
I'm pretty sure it's A.

But don't count on it
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Which are the solutions of x2 = –5x + 8?
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The answer is A
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3 years ago
Read 2 more answers
1.Graph the equation y = 6x -18:
RSB [31]

Answer:

1. Given the equation: y =6x-18                        ......[1]

The intercepts of a line are the points where the line intercepts or crosses the horizontal and vertical axes.

(A)

Horizontal intercept(x) states that the point where the line crosses the x-axis and at this point y=0

Put y=0 in equation [1]

0=6x-18 or

6x=18

<h3>⇒x=3</h3>

Ordered pair of horizontal intercept(x) = (3,0)

(B)

Vertical intercept(y) states that the point where the line crosses the y-axis and at this point x=0.

Put x=0 in equation [1]

y=6\cdot 0-18 or

y=-18

<h3>⇒y=-18</h3>

Ordered pair of vertical intercept(y) = (0,-18)

You can also see the graph  of the function y =6x-18 as shown in Figure-1.

2.

Graph the equation y+2x =4

to find the horizontal intercept and vertical intercept we follow the same process as done in 1

(A)

Horizontal intercept (x) = 2

Ordered pair = (2,0)

(B)

Vertical intercept (y) = 4

Ordered pair = (0,4)

Also, you can see these in the graph as shown in the Figure-2

3.

Given: The slope(m) of a line is \frac{3}{4}

Two lines are parallel if their slopes are equal and they have different y - intercepts.

(A).

The slope of a line parallel to it is, \frac{3}{4}

(B)

The slope of the original line is  \frac{3}{4}.

A line perpendicular to another line  has a slope that is the negative reciprocal of the slope of the other line.

Therefore, slope of a line perpendicular to it is; -\frac{1}{m} = -\frac{4}{3}

4.

The graph of the equation y =4x+5 as shown in figure 3

The x-intercept of this line is \frac{-5}{4} = -1.25

And the y-intercept of this line is y =5.

5.

Graph of the equation y = -3 represents the line as shown in figure 4.

6.

Solve the equation:

6y-18x = -18

6y = 18x-18

Divide by 6 to both sides of an equation ; we get

y = 3x-3 or

y = 3(x-1)


8 0
3 years ago
F(x)= x2<br> .<br> What is f(x) + f(x) + f(x)?<br><br> (f(x))<br> f(x) + 3<br> [3f(x)
Usimov [2.4K]

Answer:

fx2 + fx2 + fx2 = 3 f x 2

Step-by-step explanation:

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Step-by-step explanation:

\frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   = \tan \:A \\  \\ LHS =  \frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   \\  \\  =  \frac{2\sin \:2A.\cos \:2A}{\cos \:2A}   \times  \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\  \\  = 2\sin \:2A   \times  \frac{1 - 2 { \cos}^{2}A  +  1}{1 - 2 { \cos}^{2}2A  + 1 } \\  \\  = 2\sin \:2A   \times  \frac{2- 2 { \cos}^{2}A  }{2 - 2 { \cos}^{2}2A   } \\  \\   = 2\sin \:2A   \times  \frac{2(1 - { \cos}^{2}A)  }{2 (1-  { \cos}^{2}2A)   } \\  \\   = 2\sin \:2A   \times  \frac{1 - { \cos}^{2}A}{1-  { \cos}^{2}2A   } \\  \\     = 2\sin \:2A   \times  \frac{ { \sin}^{2}A}{{ \sin}^{2}2A   } \\  \\    = 2  \times  \frac{ { \sin}^{2}A}{{ \sin}2A   } \\  \\   = 2  \times  \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \:   A } \\  \\   = \frac{ { \sin}A}{ \cos \:   A }  \\  \\  = tan \: A \\  \\  = RHS \\

7 0
4 years ago
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