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o-na [289]
3 years ago
13

a population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january. the average

population starts at 900 muskrats and increases by 7 % each month. find an equation for the population p in terms of the months since january t
Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer:

P = 867(1.07)^t

Step-by-step explanation:

The population of muskrats oscillates 33 above and below average during the year, hitting the lowest value in january.

If the average value = 900 muskrats

Then the lowest = 900 - 33 = 867

It increases by 7 % each month

R = 7%

equation for the population p in terms of the months since january t will be

P = Po( 1 + R%)^t

P = 867( 1 + 0.07) ^t

P = 867(1.07)^t

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What’s the equation for a line with a x-intercept of -5 and y-intercept of 7
laila [671]

Answer:

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Step-by-step explanation:

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the fail rate for taking a bar exam in Philadelphia is 41% if 375 people take the bar exam, what is the mean for the number of f
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Let f and g be differentiable functions such that f(1) = 2, f'(1) = 3, f'(2) = -4, g(1) = 2, g'(1) = -3, g'(2) = 5. If h(x) = f
crimeas [40]

Answer:

12

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