Answer:
-8 < x< 3
Step-by-step explanation:
|2x+5| <11
there are two solutions, one positive and one negative ( remember to flip the inequality for the negative)
2x+5 <11 and 2x+5 > -11
Subtract 5 from each side
2x+5-5 < 11-5 and 2x+5-5 > -11-5
2x< 6 and 2x>-16
Divide by 2
2x/2 <6/2 and 2x/2 >-16/2
x <3 and x>-8
-8 < x< 3
x is less than 3 and x is greater than -8
open circles and -8 and 3 and a line between
9514 1404 393
Answer:
c = -3; d = 5
Step-by-step explanation:
The function is differentiable if it is continuous and the derivative is continuous.
This function will be continuous if the limit as x approaches 3 from either side is the same. From the left, the limit is ...
5(3^2) +c = 45 +c
From the right, the limit is ...
d(3^2) -3 = 9d -3
__
The derivative will be continuous if the limit as x approaches 3 from either side is the same. From the left, the limit is ...
f'(x) = 10x
= 10(3) = 30
From the right, the limit is ...
f'(x) = 2dx
= 2d(3) = 6d
__
This gives us a pair of simultaneous equations in 'c' and 'd':
45 +c = 9d -3
6d = 30
The latter tells us d = 5. Then the former tells us ...
45 +c = 9(5) -3 ⇒ c = -3
The function is differentiable if c = -3 and d = 5.
_____
<em>Additional comment</em>
With these values, the function becomes ...