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3 years ago

Write an equation of a line parallel to line GH below in slope-intercept form that passes through the point (-5, 6).

2 answers:

4 0

There are several information's of immense importance already given in the question. Based on those information's. the answer can be easily deduced.

We already know that
y = mx + b
Then
Slope for GH = (6 - 2)/(- 2 - 2)
= - 1
We already know that parallel lines have the same slope
Then
6 = -1(5) +b
6 = - 5 + b
b = 11
Then, the equation is
y = x + 11
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the last option or the fourth option.

Kisachek [45]3 years ago

3 0

Answer:

y = x + 11

Step-by-step explanation:

by using the linear equation

y = mx + b

Then

Slope for GH = (6 - 2) (- 2 - 2)

which is = - 1

1. 6 = -1(5) +b

2. 6 = - 5 + b

3. b = 11

and there you go!

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3 years ago

If tan ⁡x=12/5, and 0°

Charra [1.4K]

The value of sin(2x) is $\frac{120}{169}$

Explanation:

Given that $tan x =\frac{12}{5}$

The formula for $sin(2x)$ is $\sin (2 x)=2 \sin x \cos x$

Since, $\tan x=\frac{o p p}{a d j}$

Also, it is given that $tan x =\frac{12}{5}$

Thus, $opp=12$ and $adj=5$

To find the hypotenuse, let us use the pythagoras theorem,

$\begin{aligned}h y p &=\sqrt{12^{2}+5^{2}} \\&=\sqrt{144+25} \\&=\sqrt{169} \\&=13\end{aligned}$

Now, we can find the value of sin x and cos x.

$\sin x=\frac{\text { opp }}{h y p}=\frac{12}{13}$

$\cos x=\frac{a d j}{h y p}=\frac{5}{13}$

Now, substituting these values in the formula for sin 2x, we get,

$\begin{aligned}\sin (2 x) &=2 \sin x \cos x \\&=2\left(\frac{12}{13}\right)\left(\frac{5}{13}\right) \\&=\frac{120}{169}\end{aligned}$

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3 years ago

Twice x, plus 4, is the same as -6.

BARSIC [14]

Start by writing what is said:
2x + 4 = -6
From there just solve for x:

Subtract 4 from both sides
2x + 4 - 4 = -6 - 4
2x = -10

Divide by 2 to get x by itself
2x/2 = -10/2
x = -5

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3 years ago

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