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iogann1982 [59]
3 years ago
10

Help. Please show work. What is the greatest common factor of the two terms?

Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

I'm pretty sure it is 11664

Step-by-step explanation:

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Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had
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Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size n_1 = 49

Population standard deviation \sigma_1  = 3

Sample mean \overline x _1= 10

<u>Second population:</u>

Sample size n_2 = 64

Population standard deviation \sigma_2= 4

Sample mean \overline x_2= 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

\mathbf{H_o:\mu_1=\mu_2}

\mathbf{H_1:\mu_1\ne\mu_2}

Level of significance  = 0.01

Using the  Z-test statistics;

Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}

Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}

Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}

Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}

Z = \dfrac{-2}{\sqrt{0.43367}}

Z = \dfrac{-2}{0.658536}

Z = - 3.037

Z \simeq - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses H_o

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Answer:

Answer: <u>25 wpm</u>

Step-by-step explanation:

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