All categories

3 years ago

When the sum of 1/4 + 1/2 is divided by the product of 1/4 + 1/2 what is the quotient

1 answer:

4 0

<span>When the sum of 1/4 + 1/2 is divided by the product of 1/4 + 1/2 what is the quotient </span>2

You might be interested in

mina [271]

Subtract b and then a = (zma) - b

5 0

4 years ago

TiliK225 [7]

C, A, B

A’s rate if change:
3

B’s rate of change:
(10 - 0) / (-2 - (-4)) = 10 / 2
5

C’s rate of change:
1

4 0

3 years ago

Vaselesa [24]

Answer:

What functions there is no picture?

Step-by-step explanation:

4 0

3 years ago

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

tiny-mole [99]

$1.67 \times{10}^{ - 4}$

6 0

3 years ago