When the sum of 1/4 + 1/2 is divided by the product of 1/4 + 1/2 what is the quotient

A retiree wants level consumption in real terms over a 30-year retirement. If the inflation rate equals the interest rate she ea

Karo-lina-s [1.5K]

Answer:

Real rate = Interest rate - Inflation rate

Here, real rate will be ZERO.

When real rate of return os ZERO annual saving will be Value/Years.

Hence, available real annual savings is $15,300 ($459,000/30)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

AC = 64,<br> AB = 7x + 8, and<br> BC = 3x + 6,<br> Find BC.

iVinArrow [24]

Answer:

21

Step-by-step explanation:

AC = 64
AB = 7x + 8
BC = 3x + 6

<u>Since AC = AB + BC</u>

7x + 8 + 3x + 6 = 64
10x + 14 = 64
10x = 50
x = 50/10
x = 5

------------------

BC = 3x + 6 = 3*5 + 6 = 21

6 0

3 years ago

Set up and solve the system of equations using

nlexa [21]

54 tickets on parents

5 0

2 years ago

Read 2 more answers

A landscape business charges $50 to deliver rocks. The cost of the rocks are $27 per cubic yard. write and solve a linear equati

Nuetrik [128]

<h2>Answer: 27x + 50 = y, $266</h2>

Step-by-step explanation:

First, let's form a linear equation that will help us find out how much that will cost.

Let's set x = the cubic yards of rocks delivered and y = total cost.

First, we know that the business charges 27 dollars for every x that you buy. That can be shown with a multiplication expression:

27x

Next, we know that the business charges a fixed fee of $50 for their services. This fee would be <em>added on</em> to the amount that they charge for the rocks that you buy.

That's our linear expression! Next, we need to find out the <em>total cost</em>, y, when you need 8 cubic yards of rocks delivered, x.

To solve this, we need to substitute values for at least one of our variables.

Since 8 describes the cubic yards of rocks delivered, we can substitute 8 for x.

But we don't know y, the total cost- that's what we're solving for! In other words, we're solving for y.

Let's just substitute in what we know:

27(8) + 50 = y.

216 + 50 = y

So, we know that it would cost $266 dollars to have 8 cubic yards of rocks delivered to a site.

By the way, you can also graph your linear equation to find the corresponding y-value to 8 as another way to solve your problem.

7 0

3 years ago

An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y

Kay [80]

Answer:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

$\bar X_{1}=14$ represent the mean for sample 1 (younger)

$\bar X_{2}=20$ represent the mean for sample 2 (older)

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=31$ sample size for the group 2

$n_{2}=31$ sample size for the group 2

t would represent the statistic

System of hypothesis

We want to test if that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

The statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=31+31-2=60$

Replacing the info given we got:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0

3 years ago