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3 years ago

12

Earth has a radius of 6371 km. A pilot is flying at a steady altitude of 6.6 km above the earths surface. What is the pilots dis

tance to the horizon?

2 answers:

Fynjy0 [20]3 years ago

3 0

965.30303 would be your answer.

natta225 [31]3 years ago

3 0

Keeping in mind that the point of tangency is always a right angle, check the picture below.

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Bir işi 5 işçi 8 günde bitirdi aynı işi 4 işci kac gunde bitirir

Aleonysh [2.5K]

tam olmasada yaklaşık 6.5 günde bitter

8 0

3 years ago

5/6 minus (- 3/4) <br> HELP PLS

n200080 [17]

Answer:

In order to solve this problem, you have to find the lowest common denominator. Take multiples of both 6 and 4 and see which is the lowest you have in common.

4: 4, 8, 12, 16, 20

6: 6, 12, 18, 24

So 12 is the lowest common multiple....

5/6 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)

3/4 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)

When the denominators are the same, you can subtract the numerators. The denominator will stay 12!

Step-by-step explanation:

YAY! I want a brain

8 0

3 years ago

Read 2 more answers

Using the order of operations,what should be done first to evaluate 12÷(-6)(3)+(-2)

Maru [420]

Perentheses, probably do multiplication.

4 0

3 years ago

Read 2 more answers

In Ms. Perron’s class, 25% of the class are boys. There are 6 boys in the class. What is the total number of students in Ms. Per

Effectus [21]

Answer:

24

Step-by-step explanation:

25%= 1/4 of the class

1/4 *x=6

x=24

4 0

3 years ago

Read 2 more answers

A company wishes to manufacture a box with a volume of 36 cubic feet that is open on top and is twice as long as it is wide. Fin

Nimfa-mama [501]

Answer:

Width is 3 ft

length is 6 ft

Step-by-step explanation:

Let x = the width

Let 2x = the length

Let h = the height

We know that volume is given v = l×b×h

so we have v = volume $= x*2x*h$

$2x^2*h = 36$

$h = \frac{18}{x^2}$

surface area include 2 ends + 1 bottom and 2 sides excluding top

$S.A. = 2(x*h) + 1(2x*x) + 2(2x*h)$

$S.A. = 2xh + 2x^2 + 4xh$

we have calculate $h = = \frac{18}{x^2}$

$S.A = 2x^2 + 6x \frac{18}{x^2}$

$S.A = 2x^2 + \frac{108}{x}$

By graphing above equation we can calculate the value of x

Minimum S.A when x is 3 is the width so

2(3) = 6 is the length

$h = \frac{18}{3^2} = 2$

6 0

3 years ago