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Feliz [49]
3 years ago
10

Lucas had 18 markers. He lent 1/6 of them to Isaac and 1/9 of them to Abby. In total, how many markers did he lend?

Mathematics
1 answer:
stepladder [879]3 years ago
7 0
1/6 of 18 is 3
1/9 of 18 is 2
3+2= 5

He lent 5 markets in total
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Answer:

$3.62

Step-by-step explanation:

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AnnyKZ [126]
The answer is 1+x2 I think
4 0
2 years ago
Please help :( I will give u points
gayaneshka [121]

when there is no number with redical sign here it is equivalent to the exponent " 1/2 "

but when it is 3 under redical x that means it is x^1/3

In first one 8 ^(9/2) is same as ( redical 8 ) ^9

In part B it is (3 under redical 125)^9 = ( 125 )^ 9/3 so this also same thing

In part C it is ( 12)^2/7) but the ( redical 12 ) ^7 is equal to ( 12)^7/2 so these two are not equivalent

in part D it is 4^1/5 but ( redical 4) ^5 = 4^( 5/2 which is also not equivalent

Answer : only A and B are equivalent

3 0
3 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 72 type K batteries and a sample of 49
rewona [7]

Answer:

Given:

For battery k(sample 1):

Sample size, n = 75

Sample mean, X' = 9.41

Standard deviation = 0.723

Mean u1 =???

For battery Q(sample 2):

Sample size, n = 49

Sample mean, X' = 9.69

Standard deviation = 0.257

Mean u2 =???

Significance level = 0.05

1) The null and alternative hypotheses, will be given as:

H0 : u1 - u2 = 0

H1 : u1 - u2 ≠ 0

2) This is a two tailed test.

For the test statistic, we have :

Z_o = \frac{X'_1 - X'_2}{\sqrt{\frac{(\sigma_1)^2}{n_1} + \frac{(\sigma_2)^2}{n_2}}}

= \frac{9.41 - 9.69}{\sqrt{\frac{(0.723)^2}{75} + \frac{(0.257)^2}{49}}} = - 3.018

≈ 3.02

The Zo = - 3.02

3) For the p value, using excel, we have:

2 * P(Z > (-3.018))

= 2 * NORMDIST (-3.018, 0, 1, true)

= 0.00254

For critical value:

Zcritical = Za/2 = 0.05/2

Zcritical = 0.025

We have alternative hypothesis,

H1 : u1 - u2 ≠ 0.

Therefore we reject null hypothesis H0 if Zo > Zcritical

4) We reject null hypothesis H0 if Zo > Zcritical. At 0.05 level of significance, there is not enough evidence to conclude that mean u1 and mean u2 are different.

4 0
3 years ago
Help me answer this please ​
Talja [164]

Answer:

(-6,-4) make them both negative

3 0
3 years ago
Read 2 more answers
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