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GarryVolchara [31]
2 years ago
10

A box of cereal states that there are 99 calories in a 3/4 cup serving. What is the unit rate for calories per cup? How many cal

ories in 4 cups of cereal
Mathematics
2 answers:
sergejj [24]2 years ago
4 0
Divide 99 calories by 4, then multiply that amount by 3 to get 132 calories. So per cup, there are 132 calories. Multiply 132 by 4 and you should get your answer which is 528.
galben [10]2 years ago
3 0

Answer:

Hello There!

According to the question,

It is said that we have to find calories in 4 cups.

First we have to find in each cup.

So

\frac{3}{4} \times x = 99 \\ \\  so \: x = 99 \times  \frac{4}{3}  \\  \\

simplify 99 and 3 then it will look like

33 \times  \frac{4}{1}

1 has no value so 33×4=132 calories

Now it is in each cup or 1 cup.

To find in 4 cups, multiply 132×4

132 \times 4 = 528

So 528 calories is the answer.

\Large\textsf{Hope \: It \: Helped}

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At a local high school football game, twice the number of students attended as adults. If student tickets were $6.50, adult tick
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Answer:

454

Step-by-step explanation:

set up a system of equation

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8 0
3 years ago
Given: 1 and 2 are supplements, and 3 and 2 are supplements.
Ronch [10]

The <em><u>correct answers</u></em> are:

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Since we are told that ∠2 and ∠3 are supplementary, their measures sum to 180° and they are the second answer.

We know that m∠1 + m∠2 = 180° and m∠2 + m∠3 = 180°.  We can substitute "m∠2 + m∠3" for 180° in the first equation; this is the substitution property.

To isolate m∠1 on the right, we will subtract m∠2 from each side, and get that m∠1 = m∠3 and the angles are congruent.


5 0
2 years ago
Read 2 more answers
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fiasKO [112]

Answer:

Option A

Option B

Option E

Option G

Option A and E go together

and

Option B and G go together.

4 0
3 years ago
10 points?...1) must be quick to answer,2) must be reasonable answer,3) Show explanation for your answer
Ilia_Sergeevich [38]
Your answer is
{x}^{2}  \div   {2} {z}^{9}
because the numbers raised to negative powers must be flipped over the divisor to become positive. Then, when multiplying 2 and z, you add their exponents.
3 0
3 years ago
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