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Svetach [21]
3 years ago
7

X4+4x3+2x2+x+4 divided by x2+ 3x

Mathematics
2 answers:
Lesechka [4]3 years ago
3 0

Answer:

x^2+x-1 + ((4x+4)/(x^2+3x))

Step-by-step explanation:

We need to write the polynomial in descending order

Then, grab the term with the highest  power from the polynomial and divide it by the term with highest power from the polynomial located at the other side of the division symbol (this polynomial would be x^2 + 3x)

The result (x^4 / x^2) = x^2

This term will be part of the solution, and will be use to start the process of division.

This process start with the previous obtained term (x^2), which will be multiplied by the polynomial from the other side of the division symbol (x^2 + 3x).

The result another is another polynomial

This new polynomial will be multiply by negative 1

The new polynomial is then added to the poly (X^4+4x^3+2x^2+x+4)

The result will constitute a new poly, that will be use as the remaining of the division.

Since, our reamining differs from zero, and we still have member to simplify, we repeat the step 1 using the remaining as the new poly that needs to be divided by (x^2 + 3x).

The attached picture explains the whole procedure.

Eduardwww [97]3 years ago
3 0

Answer:

B.  x4 + 4x3 + x2 + 4x

Step-by-step explanation:

got it right on the assignment

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Answer:

to find area, multiply the two sides together. since it tells us that this is a square we can assume both sides are the same length (315.2). multiply 315.2 and 315.2, and you get 99,351.04.

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3 years ago
Which of the following points is no coplanar with points A,C, and D
Leni [432]

Answer:

Option A is correct.

Point T is not co-planar with points A, C and D

Step-by-step explanation:

Co-planar states that those which lies in the same plane.

Point A, C and D are lies in the Plane AEDC.

Since, this plane also contains points S and U.

Thus, point A, C , D , E, S  and U are co-planar

but point T does not lie in the plane  AEDC.

Therefore, point T is not co-planar with points A, C and D

3 0
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3x+5 and g(x)= x^2-6 find F(4)
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Answer:

Which expression has a greatest common factor of 3h?

Step-by-step explanation:

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3 years ago
What's the curved line with the two parallel lines
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It means that those 2 angles are the exact same length
7 0
4 years ago
Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane passing through (2 comma 0
SVETLANKA909090 [29]

Answer:

The volume of the tetrahedron is:

\frac{50}{3}=16.667

Step-by-step explanation:

The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.

The equation of the plane formed by the three points is:

Points: (2,0,0);(0,5,0);(0,0,4)

\pi :\frac{x}{2} +\frac{y}{5} +\frac{z}{4} =1

It can also be expressed as:

10x + 4y+5z=20

We have to calculate the triple integral, therefore we must define the domain:

The values of x are given by:

0≤x≤2

We will integrate the values of y between the y = 0 axis and the line formed when z = 0:

z=0 ⇒ 10x + 4y=2 ⇒ y=\frac{20-10x}{4} =

0\leq y \leq 5-\frac{5}{2}x

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20

10x + 4y+5z=20 ⇒ z=\frac{20-10x-4y}{5} =4-2x-\frac{4}{5}y

0\leq z \leq  4-2x-\frac{4}{5}y

The volume of the tetrahedron is:

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \ \ \ \int\limits^{4-2x-\frac{4}{5}y }_{0} {z} \, dz\, dy \,dx

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \frac{z^2}{2}|^{4-2x-\frac{4}{5}y}_0\, dy \,dx

\frac{z^2}{2}|^{z=4-2x-\frac{4}{5}y}_{z=0}=\frac{5}{25}(5x+2(y-5))^2

\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} {\frac{5}{25}(5x+2(y-5))^2}\, dy \,dx

\int\limits^{2}_{0} {-\frac{25}{6}(x-2)^3} dx=-\frac{25}{24} (x-2)^4|^{2}_{0}=\frac{50}{3}

6 0
4 years ago
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