That would be choice 3
middle term = -3mn-8mn = -11mn and last term = + 2n^2
1.4375
<u>Step-by-step explanation:</u>
Step 1:
Let the given equation be 
To find X simplification of terms using BODMAS ( Brackets Orders Division Multiplication Addition Subtraction) is done as follows.
Step 2:
Let us expand the equation as 
Step 3:
Let us expand it further as 
Step 4:
To find X segregate X in one side and all other remaining terms in other side as follows
After the simplification the numerical value is
Step 5:
Keep X along one side and bring 48 to the denominator of another side to find X as follows
And the value of X is 1.4375
If t=-3 (hopefully it does) then it's 6+-12/10. This is -6/10=-3/5
<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
Answer:
0.5 Inches per hour
Step-by-step explanation:
Most normal people won't know exactly what unit rate is, or how to calculate it. So I'm here to help!
This is a fraction equal to
6 inches ÷ 12 hours
We want a unit rate where
1 is in the denominator,
so we divide top and bottom by 12
6 inches ÷ 12
12 hours ÷ 12
=
0.5 inches
1 hour
=
0.5 inches
hour
= 0.5 inches per hour
Glad I was able to help!
