A warm fronts move from the south to the north
<u>Explanation</u>:
A warm front are formed when a warm mass of air is pushed into a cold air mass. Since the warm air mass at surface rises above the cold mass of air they often causes stormy weathers. Also due the difficulty of warm air in pushing the cold dense air across the surface of the earth make the warm fronts to move slower when compared to cold fronts. Unstable air produces thunderstorms around the warm fronts. solid red line with red, filled-in semicircles is used to represent a warm front on the map.
Hey You!
I believe the correct answer to your question is: Endangered Species. (Also called threatened species).
I Really Hope This Helped You, Good Luck With Your Studies! =)
Answer:
The t-test
Explanation:
<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>
In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:
Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:
where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.
<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>
<u>50%</u> of offspring will have brown eyes
Explanation:
A heterozygous individual will have the genotype <em>Rr </em>while an individual who is homozygous recessive will have the genotype <em>rr.</em> A cross between the two will result in offspring with phenotype <em>Rr</em> and <em>rr</em> in the ratio of 1 : 1. This can be observed from the Punnet square attached. The same is the case for the phenotype. The ration of brown eyes to red eyes will be approximately 1 : 1
The probability of the son being colorblind is 100% :)