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Nataliya [291]
3 years ago
13

Simplify. tan(-x).cot(-x)

Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

= 1

Step-by-step explanation:

tan(-x).cot(-x) 

tan(-x)  × cot(-x)

Note : cot =reciprocal or inverse of  tan = 1/ tan

Therefore

tan(-x)  × cot(-x)

= tan(-x)  × 1/tan(-x)

= tan(-x)  ÷ tan(-x)

= 1

I hope this was helpful, please rate as brainliest

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After 8 years, how much will brandon have saved in interest by consolidating the two balances? a. $581.76 b. $194.40 c. $256.32
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C

Step-by-step explanation:

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1 year ago
find the number of positive integers not exceeding 100 that are either odd or the square of an integer.
Ivenika [448]

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55

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50 odd numbers and 3 even square numbers

3 0
1 year ago
For the graph x = 12 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your a
blagie [28]
Check the picture below.

that's the line of x = 12, just a straight vertical line, notice the green line, that's parallel to it, and the red line, that's perpendicular to it.

let's pick two points for each to get their slopes, hmm say for the green one (5,2) and (5,4)

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad 
(\stackrel{x_2}{5}~,~\stackrel{y_2}{4})
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-2}{5-5}\implies \stackrel{und efined}{\cfrac{2}{0}}

and for the red one hmmm (3,2) and (7,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\qquad 
(\stackrel{x_2}{7}~,~\stackrel{y_2}{2})
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-2}{7-3}\implies \cfrac{0}{4}\implies 0

8 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. 7^3*7^x
myrzilka [38]
The answer is A and F
5 0
2 years ago
Read 2 more answers
The price of a cellular telephone plan is based on peak and nonpeak service. Kelsey used 45 peak minutes and 50 nonpeak minutes
Oxana [17]
We can build a system of two linear equations with two unknowns with the info provided in the problem, one with Kelsey info and one with Mitch info like so:
Lets call p the amount on peak minutes and n the amount of non-peak minutes:
45p + 50n = 27.75
70p + 30n = 36
lets reduce the equations dividing the first by 5:
9p + 10n = 5.55
<span>70p + 30n = 36
</span>now, to eliminate n, lets multiply the first equation by -3 and add the two equations:
-27p - 30n = -16.65
<span>70p + 30n = 36
</span>----------------------------
43p + 0 = 19.35
p = 19.35<span>/43
p = 0.45
therefore the peak rate is $0.45 per minute
lets substitute in one of the original equations this result:
</span><span>45p + 50n = 27.75
</span>45(0.45) + 50n = 27.75
20.25 <span>+ 50n = 27.75
50n = 27.75 - 20.25
50n = 7.5
n = 7.5/50
n = 0.15
therefore the non-peak rate per minute is $0.15</span>
5 0
2 years ago
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