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raketka [301]
3 years ago
7

Can someone do the whole thing

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

1

Step-by-step explanation:

y=mx+b,  equation for slope-intercept line

we can work out the equation based on given two points (1,1) and (7,4)

  • m=(y2-y1)/(x2-x1)= (4-1)/(7-1)= 3/6= 1/2

y=1/2x+b

For (1,1)

  • 1= 1/2+b ⇒ b= 1/2

For (7,4)

  • 4=7*1/2+b ⇒ b= 1/2

So we get

  • y= 1/2x+1/2

The answer is 1 for question mark

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Simplify –2x3y × xy 2.
user100 [1]

-2x^3y\cdot xy^2=-2x^{3+1}y^{1+2}=-2x^4y^3

Used:

a^n\cdot a^m=a^{n+m}

Answer: C. –2x^4y^3

8 0
3 years ago
HELP ASAP
AlekseyPX
We’ll subtract the exponent in the denominator from the exponent in the numerator, keeping the base the same. Cant be simplified, because the base of the expression in the numerator is y and the base of the expression in the denominator is x.
4 0
3 years ago
Using Euler’s formula, how many edges does a polyhedron with 20 faces and 12 vertices have?
astra-53 [7]

Euler's formula for a polyhedron is given by:

\begin{gathered} F+V=E+2 \\ \text{where,} \\ F=\text{faces} \\ V=\text{vertices} \\ E=\text{edges} \end{gathered}

Make E, the subject of the formula:

\begin{gathered} F+V=E+2 \\ E=F+V-2 \end{gathered}

Put F = 20, V = 12, to obtain E,

\begin{gathered} E=20+12-2 \\ E=30 \end{gathered}

Therefore, there are 30 edges

3 0
1 year ago
Which ordered pair makes both inequalities true?
Tatiana [17]

The ordered pair which makes both inequalities true is: D. (3, 0).

<h3>How to determine ordered pair?</h3>

In Mathematics, an inequality can be used to show the relationship between two (2) or more integers and variables in an equation.

In order to determine ordered pair which makes both inequalities true, we would substitute the points into the inequalities as follows:

At (0, 0), we have:

y > -2x + 3  

0 > -2(0) + 3

0 > 3 (false).

y < x – 2

0 < 0 - 2

0 < -2 (false)

At (0, -1), we have:

y > -2x + 3  

-1 > -2(0) + 3

-1 > 3 (false).

y < x – 2

-1 < 0 - 2

-1 < -2 (false)

At (1, 1), we have:

y > -2x + 3  

1 > -2(1) + 3

1 > -1 (true).

y < x – 2

1 < 1 - 2

1 < -1 (false)

At (3, 0), we have:

y > -2x + 3  

0 > -2(3) + 3

0 > -3 (true).

y < x – 2

0 < 3 - 2

0 < 1 (true).

Read more on inequalities here: brainly.com/question/24372553

#SPJ1

3 0
2 years ago
1. The midpoint of KL is M(5, -7). One endpoint is K(9,-7). Find the coordinates of the other endpoint L.
kirill115 [55]

Answer:

L (1, - 7 )

Step-by-step explanation:

give endpoints (x₁, y₁ ( and (x₂, y₂ )  then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )

use the midpoint formula and equate to corresponding coordinates of M

\frac{9+x}{2} = 5 ( multiply both sides by 2 to clear the fraction )

9 + x = 10 ( subtract 9 from both sides )

x = 1

and

\frac{-7+y}{2} = - 7 ( multiply both sides by 2 )

- 7 + y = - 14 ( add 7 to both sides )

y = - 7

Then L  = (1, - 7 )

8 0
2 years ago
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