What is the quotient (3x^2+8x-3)/ (x+3)

Mathematics

1 answer:

Dvinal [7]2 years ago

6 0

Answer:

The quotient ix 3x - 1.

Explanation:

Use Long division:

3x - 1 <------------quotient.

---------------------

x + 3) 3x^2 + 8x + 3

3x^2 + 9x

-------------

-x + 3

-x - 3

------

6 <---------remainder.

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Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

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$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .