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trapecia [35]
4 years ago
12

What is the line of symmetry of the parabola y=x2+6x-9? x=6 x=-9 x=-3

Mathematics
1 answer:
Elodia [21]4 years ago
7 0

Answer:

In the given parabola  y=x^2+6x-9  the line of symmetry is the axis x  = -3

Step-by-step explanation:

Here, the given equation of the parabola is : y=x^2+6x-9

Now, in the <u>Standard Form of the Parabolic Equation</u>: y=ax^2+bx+c,

The axis of symmetry is a vertical line x  = −b / 2 a .

Now, here comparing the given parabolic equation with teh standard form, we get  :  

a  = 1 , b = 6 and c  = -9

So, the axis of symmetry =  -\frac{b}{2a}  =- \frac{6}{2(1)} =  -3

Hence, here in the given parabola  y=x^2+6x-9  the line of symmetry is the axis x  = -3.

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a_{i} = \frac{(-3)^{i}}{4\cdot i!} converges.

Step-by-step explanation:

The convergence analysis of this sequence is done by Ratio Test. That is to say:

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A car traveling 65 mph leaves 25 ft skid mark. What is the ratio of the speed (mph) to the lenght of skid marks (ft) give you an
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1. Find the equation of the line passing through the point (2,−4) that is parallel to the line y=3x+2 y= 2. Find the equation of
tamaranim1 [39]

Answer:

Step-by-step explanation:

1) Parallel lines have same slope

y =  3x + 2

m = 3

(2, -4)  ;  m = 3

equation:  y - y1 = m (x - x1)

y - [-4] = 3(x - 2)

y + 4 = 3x - 6

y = 3x - 6 - 4

y = 3x - 10

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Slope the line perpendicular to  y = 18x + 2,  m2 = -1/m1 = -1/18

m2 = -1/18

(1 , -5)

y-[-5]=\frac{-1/18}(x-1)\\\\y+5=\frac{-1}{18}x + \frac{1}{18}\\\\y=\frac{-1}{18}x+\frac{1}{18}-5\\\\y=\frac{-1}{18}x+\frac{1}{18}-\frac{5*18}{1*18}\\\\y=\frac{-1}{18}x+\frac{1}{18}-\frac{90}{18}\\\\y=\frac{-1}{18}x-\frac{89}{18}\\\\

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