6 sides on a dice 1-6 numbers probability is 4/6 or 2/3
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
A
Step-by-step explanation:
It would be A, because EQUAL lateral is all sides are equal
Answer:
x = 15
Step-by-step explanation:
The two angles form a straight line so they add to 180 degrees
3+6x + 5x+12 = 180
Combine like terms
11x+15 = 180
Subtract 15 from each side
11x+15-15 =180-15
11x = 165
Divide by 11
11x/11 =165/11
x =15
I would have to say 85 but thats just a guess.
