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Dominik [7]
4 years ago
6

Which of the following are polynomials?

Mathematics
1 answer:
zubka84 [21]4 years ago
6 0
Answer is b hope this helps
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-6(-3 + x) = 6 <br>solve for x please ​
Anna71 [15]

-6(-3+x) = 6

-3+x = 6+6

-3+x=12

-3x=12

x=12^3

x=2

4 0
2 years ago
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How to simplify 3sin^2x + 3(1-sin^2x)
EleoNora [17]

\bf \textit{Pythagorean Identities}\\\\sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\[-0.35em]\rule{34em}{0.25pt}\\\\3sin^2(x)+3[1-sin^2(x)]\implies 3sin^2(x)+3cos^2(x)\\\\\\\stackrel{\textit{common factor}}{3[sin^2(x)+cos^2(x)]}\implies 3(1)\implies 3

5 0
3 years ago
Resolver la ecuación trigonometrica: Senx^2=Cosx^2-Senx
Arisa [49]
I would help but I don't speak your language do u speak English not being mean
8 0
4 years ago
If a function f ( x ) has values f ( 4 ) = 6 and f ( 8 ) = 18, use what you have learned about function patterns to find f ( 16
taurus [48]

Answer:

a) f(16) = 42

b) f(16) = 54

c) f(16) = 162

d) f(16) = 30

Step-by-step explanation:

a) y = mx + b ∧ m = (f(8) - f(4))/(8-4) ⇒ m = (18 - 6)/(8 - 4) = 3

b = y - mx = 6 - 3(4) = 6 - 12 = - 6

f(16) = 3(16) - 6 = 42

b) y = kxⁿ ∧ f(4) = 6 = k4ⁿ ∧ f(8) = 18 = k8ⁿ ⇒ 18/6 = (k8ⁿ)/(k4ⁿ) ⇒ 3 = 2ⁿ

n = ㏑(3) / ㏑(2) ⇒ k = y/xⁿ ⇒ k = 6/4ⁿ = 2/3

f(16) = 2/3 × 16ⁿ = 54

c) y = aeᵇˣ ∧ f(4) = 6 = aeᵇ⁴ ∧ f(8) = 18 = aeᵇ⁸ ⇒ 18/6 = (aeᵇ⁸)/(aeᵇ⁴) ⇒ 3 = e⁴ᵇ

b = ㏑(3/4) ∧ a = y / eᵇˣ ⇒ a = 6 / e⁴ᵇ = 2

f(16) = 2eᵇ¹⁶ = 162

d) y = a㏑(bx) ∧ f(4) = 6 = a㏑(b4) ∧ f(8) = 18 = a㏑(b8)

⇒ 18 - 6 = a㏑(b8) - a㏑(b4) ⇒ 12 = a㏑(8b/4b) ⇒ a = 12 / ㏑(2)

f(4) = 6 = a㏑(4b) ⇒ b = (√2)/4

f(16) = a㏑(b16) = 30

3 0
3 years ago
if all 10 players scored the same number of points, how many would each have to score to get a total of 230
Aliun [14]

Answer:

<u>Each player would have to score 23 points.</u>

Step-by-step explanation:

To answer this question, you must do 230 ÷ 10!

The answer to this is 23.

You can double check your answer by multiplying 23 by 10!

3 0
2 years ago
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