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denis-greek [22]
3 years ago
15

The equation 2003-02-05-00-00_files/i0070000.jpg can be used to model a person’s future income. S = future salary, p = current s

alary, r = rate of increase(% in decimal form), and t = time in years. Bob’s salary increases by 5% each year. If he starts at $35,000 per year, what will his salary be in 5 years? A. $36,750 B. $44,670 C. $43,750 D. $50,000
Mathematics
2 answers:
stiks02 [169]3 years ago
3 0
I cannot see the file !!
suter [353]3 years ago
3 0

Answer:

The equation S=p(l+r)^t can be used to model a person’s future income. S = future salary, p = current salary, r = rate of increase(% in decimal form), and t = time in years. Bob’s salary increases by 5% each year. If he starts at $35,000 per year, what will his salary be in 5 years?

Step-by-step explanation:

So we want to find S

We know that P=35,000

We know that r = 0.05 (5% in decimals)

We know that t = 5

I don't know what I is so I'm going to assume it's 1?

S = 35 000 (1 + 0.05)^5

So

S = $44,669.85 = $44,670

So B :)

I hope this helps!!

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A new cream was developed to reduce the irritation caused by poison ivy. To test the effectiveness, researchers put an ad online
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Single Blind (option 1)

Step-by-step explanation:

The subjects don't know which cream they have but the technicians do.

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4 0
2 years ago
Find the zeros for 2x^2-24=26. what id the positive value of x?
Oksana_A [137]

Answer:

x=5

Step-by-step explanation:

move the constant to the right

calculate

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simplify the equation

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6 0
2 years ago
A study was performed to investigate whether teens and adults had different habits when it comes to consuming meat-free meals. I
Elden [556K]

Answer:

H₀ should be rejected at CI 95% .

Then the proportion of adults with 95 % CI is bigger than the proportion of teen

Step-by-step explanation:

From adult sample:

n₂ = 2323

x₂ = 1601

p₂ = 1601 / 2323         p₂  = 0,689       or    p₂ = 68,9%

From teen sample:

n₁ = 875

x₁ = 555

p₁ = 555/ 875           p₁  = 0,634          or    p₁  = 63,4

Values of p₁  and  p₂   suggest that the proportion of adults consuming at least one meat free meal per week is bigger than teen proportion.

To either prove or reject the above statement we have to develop a difference of proportion test according to:

Hypothesis test:

Null Hypothesis                   H₀             p₁  =  p₂

Alternative Hypothesis       Hₐ             p₂  > p₁

So is a one-tail test to the right

We can establish a confidence interval of 95 % then  α = 5 %

or    α = 0,05

As the samples are big enough we will develop a z test

Then  z(c)  for α = 0,05   from z table is     z(c) = 1,64

To calculate z(s)

z(s) = ( p₂  -  p₁ ) / √p*q* ( 1/n₁  + 1/n₂ )

where p = ( x₁ + x₂ ) / n₁ + n₂       p = 555 + 1601 / 875 + 2323

p = 2156/3198       p = 0,674

and   q = 1 - 0,674        q = 0,326

z(s) = ( 0,689 - 0,634 ) / √0,674*0,326 ( 1/875 + 1 / 2323

z(s) = 0,055/ √ 0,2197 ( 0,00114 + 0,00043)

z(s) = 0,055/ √0,2197* 0,00157

z(s) = 0,055/ √ 3,45*10⁻⁴

z(s) = 0,055 / 1,85*10⁻²

z(s) = 5,5/1,85

z(s) = 2,97

Comparing  z(s) and z(c)     z(s) > z(c)

Then z(s) is in the rejection region we reject H₀.

We can claim that the proportion of adult eating at least one meat-free meal is bigger than the proportion of teen

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