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coldgirl [10]
3 years ago
13

3.The coordinates of the vertices of quadrilateral ABCD are A(0,4), B(4,2), C(2,-1) and D(-2,1). Jorge states that quadrilateral

ABCD is a parallelogram. Prove or disprove Jorge’s statement.
Mathematics
1 answer:
zmey [24]3 years ago
4 0
A parallelogram<span> is a simple (non-self-intersecting) quadrilateral with two pairs of parallel sides. Plotting the points given above would give as a parallelogram where line made by AB is parallel and congruent with line CD. Hope this answers the question.</span>
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Use the Pythagorean theorem to find the distance between the two points ANB round your answer to the nearest hundredth
jek_recluse [69]

Answer:

5.39 units

Step-by-step explanation:

Pythagorean theorem: a^{2} + b^{2} = c^{2}

Let point (-2,1) be C

Line segment AC would be 2 units long.

Line segment BC would be 5 units long.

Insert the length of the line segments in to the Pythagorean theorem

2^{2} + 5^{2}

4 + 25 = 29

\sqrt{29} ≅ 5.385

6 0
3 years ago
The value of a piece of equipment is decreasing at a rate of 7,5% yearly. If the equipment
SCORPION-xisa [38]

Answer:

y=930 x 075^x

Step-by-step explanation:

y is the price after the amount of years x being plugged into the equation. 930 is what you started with. 7.5 is what is being decreased so divide that by 100 and you get 0.075 plug in the amount of years into x and you have your equation

4 0
3 years ago
Zaire sells 24 slices of blueberry pie and 15 slices if cherry pie. what was his profit?
TiliK225 [7]
39 depending on the prices but 39 is how many he sold
7 0
3 years ago
Now simplify the y-terms to get the equation of the parabolic path. You do not need to expand the x-term. (2 points) Hint: Squar
aalyn [17]

The simplified equation of (x - 10)^2 + (y- 6)^2 = 4^2 is y = 6+  \sqrt{16 - (x - 10)^2}

<h3>How to determine the simplified equation?</h3>

The complete question is added as an attachment

The equation is given as

(x - 10)^2 + (y- 6)^2 = 4^2

Subtract (x - 10)^2 from both sides

(y- 6)^2 = 4^2 - (x - 10)^2

Evaluate 4^2

(y- 6)^2 =16 - (x - 10)^2

Take the square root of  both sides

y- 6= \sqrt{16 - (x - 10)^2}

Add 6 to both sides

y = 6+  \sqrt{16 - (x - 10)^2}

Hence, the simplified equation of (x - 10)^2 + (y- 6)^2 = 4^2 is y = 6+  \sqrt{16 - (x - 10)^2}

Read more about simplified equation at:

brainly.com/question/723406

#SPJ1

6 0
2 years ago
16 + 4x + 2x-3x + x = 0
NemiM [27]
16 + 4x + 2x - 3x + x = 0

First, simplify 16 + 4x + 2x - 3x + x to get 16 + 4x. / Your problem should look like: 16 + 4x = 0
Second, subtract 16 from both sides. / Your problem should look like: 4x = -16
Third, divide both sides by 4. / Your problem should look like: x = -\frac{16}{4}
Fourth, simplify \frac{16}{4} to get 4. / Your problem should look like: x = -4

Answer: x = -4

4 0
3 years ago
Read 2 more answers
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