Question

What the vertex of the graph of y=-x^2

Answer 1

Since there is no specified y-intercept, the vertex is at (0, 0).

Answer 2

First let's define vertex: A point on the curve with a local minimum or maximum of curvature. If we look for the minimum and maximum value of the equation y=x^2+5: minimum value X=0, substitute in the equation to get the maximum value of Y y = 0^2 + 5y = 0 + 5y= 5 so the ordered pair is (0,5) Hope That Helped =D