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Zanzabum
3 years ago
9

X^2-5x-6 X^2+3x-40 X^2+3x-4

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

x² - 5x - 6

= x² + x - 6x - 6

= x(x + 1) - 6(x + 1)

= (x - 6) (x + 1)

x² + 3x - 40

= x² + 8x - 5x - 40

= x(x + 8) -5(x + 8)

= (x - 5) (x + 8)

x² + 3x - 4

= x² + 4x - x - 4

= x(x + 4) -1(x + 4)

= (x - 1) (x + 4)

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Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
In 5 minutes a conveyor belt moves 300 pounds of receyclable aluminum from the delievery truck a smaller belt moves the same qua
ladessa [460]

Answer:

It will take 3.214 minutes.

Step-by-step explanation:

<em>It is given that, the conveyor belt transports 300 cans in 5 mins and the smaller belt transports 300 cans in 9 minutes.</em>

Thus , the speed of conveyor belt is,

= \frac{300}{5} = 60 cans per minute

and of smaller belt is,

=  \frac{300}{9} = \frac{100}{3} cans per minute

Thus, when both are used together,

<em>conveyor belt will transport (60)(t) cans and smaller belt will transport ( \frac{100}{3})(t) cans per minute.</em>

Thus the equation becomes,

300 = (60)(t) + (\frac{100}{3})(t) = (\frac{280}{3})(t)

t = \frac{(300)(3)}{280} = \frac{45}{14} = 3.214 minutes

3 0
3 years ago
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