Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:
Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong.
PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.
PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.
The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable).
A. 8.53 units is the length of the straight which is perpendicular to the straight line CD
Answer:
A true statement
Step-by-step explanation:
WHAT R THE STATEMENTS
Coefficient of x is less than 0 then it's across the y axis
So f(x)=2^x ---> g(x) = 2^-x
Then translating it up 5 units, should be g(x) = 2^(-x) + 5
Answer is the last one
g(x) = 2^(-x) + 5
