The population of Thunder Bay has been increasing over the last 10 years. The
1 answer:
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Answer:
The worth of truck is $2,201 more after 2 years than after 3 years.
Step-by-step explanation:
Given:
The value of truck is depreciate per year using above formula.
We need to find how much more worth of truck after 2 years than 3 years.
First we find the worth of truck after 2 years, put x=2 into formula
The worth of truck after 2 years would be $27,508
Now we find the worth of truck after 3 years, put x=3 into formula
The worth of truck after 2 years would be $25,307.36
Now we find difference of both value.
Difference = 27508-25307.36 = $2,201
Hence, The worth of truck is $2,201 more after 2 years than after 3 years.
<h3>Answer: 36pi (choice b)</h3>
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Explanation:
Let x = length of side BC
This is the height of the cylinder. Think of a can that is laying on its side. The radius of this can or cylinder is CD
If point B has x coordinate of 12, and BC is 12 units long, this must mean point C has x coordinate of 12-x. This is plugged into the function to show that CD has a length of exactly
This is the radius of the cylinder
The volume of a cylinder is
Plug in the radius and height mentioned to get this function in terms of x
That simplifies to
or
Ignore the pi portion for now.
We wish to maximize the function f(x) = 12x-x^2
Use either calculus (specifically derivatives) or a graphing calculator to find that the vertex is at (6, 36)
This means x = 6 leads to the largest f(x) value being 36.
Therefore, the volume V is maxed out when x = 6 and we get a max volume of 36pi cubic units.