Question

A national study found that 44% of college students engage in binge drinking. Using the 68-95-99.7 rule to describe the sampling distribution of a randomly selected group of 200 college students who engage in binge drinkning.

Answer 1

Answer:

$\bf \sigma = 0.0351$

Step-by-step explanation:

68–95–99.7 Rule : It also known as the empirical rule and it is a shorthand used to calculate the percentage of values that lie within a range around the mean in a normal distribution with the width of several standard deviation

μ = π = sample proportion

  = 44 %

  = 0.44

Population standard deviation proportion,

$\sigma = \sqrt{\frac{\pi \times (1 - \pi)}{n}}\\\\\implies \sigma= \sqrt{\frac{0.44 \times (1 - 0.44)}{200}}\\\\\implies\bf \sigma = 0.0351$