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3 years ago

-6x + 8 > 32 plz help i will give you 30 points

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Hello there!

Answer:

x<-4

*The answer must have a negative sign and less than symbol sign.*

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

First, you subtract by 8 from both sides of an equation.

$-6x+8-8>32-8$

Then, simplify.

$-6x>24$

You can also multiply by -1 from both sides of an equation.

$(-6x)(-1)$

And then, simplify.

$6x$

Next, divide by 6 from both sides of an equation.

$\frac{6x}{6}$

And finally, simplify and solve. Divide by the numbers.

$24/6=4$

Final answer: → $x$

Hope this helps!

Thanks!

-Charlie

Have a great day!

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The function g is defined as follows for the domain given. g(x) = 2 - 2x , domain = \{- 1, 0, 1, 2\} Write the range of g using

Musya8 [376]

Explanation:

The function is given below as

$g(x)=2-2x$

The set of domains is given below as

$\lbrace-1,0,1,2\rbrace$

Step 1:

Put x=-1

$\begin{gathered} g(x)=2-2x \\ g(-1)=2-2(-1) \\ g(-1)=2+2 \\ g(-1)=4 \end{gathered}$

Step 2:

Put x=0

$\begin{gathered} g(x)=2-2x \\ g(0)=2-2(0) \\ g(0)=2 \end{gathered}$

Step 3:

Put x=1

$\begin{gathered} g(x)=2-2x \\ g(1)=2-2(1) \\ g(1)=2-2 \\ g(1)=0 \end{gathered}$

Step 4:

Put x=2

$\begin{gathered} g(x)=2-2x \\ g(2)=2-2(2) \\ g(2)=2-4 \\ g(2)=-2 \end{gathered}$

Hence,

The range of g(x) using set notation will be

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Hence,

The graph of g(x) is given below as

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1 year ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

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3 years ago

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Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that

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From the relation, we have that

Ao = 1

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