Step-by-step explanation:
area of square = 1
area of a circle in square =
bu estimate ![p^ = X/n = 760/1000 = 0.76Therefore, [tex]\frac{\pi }{4} \approx 0.76](https://tex.z-dn.net/?f=p%5E%20%3D%20X%2Fn%20%3D%20760%2F1000%20%3D%200.76%3C%2Fp%3E%3Cp%3ETherefore%2C%20%3C%2Fp%3E%3Cp%3E%0A%5Btex%5D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%5Capprox%200.76)
b) if n tend to infinity
You have to add all of your frequency’s together and divide by 6 for the 6 scores. your mean would be 2
Answer:
14
Step-by-step explanation:
We solve this by using 2 to open the bracket
(3+4)2 is the same as 2(3+4)
2(3)+2(4)
=6+8
=14
OR
(3+4)2 is the same as 2(3+4)
So we can solve the one inside the bracket first
=2(7)=14
The answer is -8
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Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
-----------------------
The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
Answer:
24, 64
Step-by-step explanation:
If I add 1 to a multiple of 8 I get a multiple of 5, what multiples of 8
meet the condition? (Mention at least 2 of them)
3 x 8 + 1 = 25
8 x 8 + 1 = 65
