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Paha777 [63]
3 years ago
12

How to do domain and range

Mathematics
1 answer:
Ann [662]3 years ago
8 0
A domain is a set of all first elements of ordered pairs (x-coordinates) The range is the set of second elements of ordered pairs (Y-coordinates) Domain and range can be seen clearly on the graphic
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Joe spends $8 on lunch and 6.50 on dry cleaning.He also buys 2 shirts that cost the same amount. Joe spends a total of $52.What
emmainna [20.7K]
52-8=44
44-6.50=37.50
37.50/2=18.75
18.75 per shirt
4 0
3 years ago
Read 2 more answers
A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a)
Alla [95]

Answer:

A(t) = 90e^0.12t ;

299 mg

Step-by-step explanation:

General Continous growth rate equation :

A = Pe^rt

A = amount present, t years after year of initial amount.

Here,

P = 90 mg, amount in year 2000

r = rate = 12% = 0.12

t = years after 2000

Therefore,

A is written as ;

A(t) = 90e^0.12t

Amount present in year 2010 ;

t = 2010 - 2000 = 10

A(10) = 90e^0.12(10)

A(10) = 90 * e^1.2

= 90 * 3.3201169

= 298.81052

= 299 mg

5 0
3 years ago
Two adjacent supplementary angles are
mars1129 [50]
Adds up to 180 degrees. For two angles to be non-supplementary the must sum to anything other than 180 degrees, to be non-adjacent they can't share a common side (Ray)
3 0
3 years ago
Read 2 more answers
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
I need these answers by 1:30
hodyreva [135]

Answer:

its 4

Step-by-step explanation:

because u divied

3 0
3 years ago
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