A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a) Write a formula for the amount present, A (in mg), t years after 2000. MathPAD Response msnViewer_resp_str_c04q_go_2_006_1_svg ViewEdit (b) How much will be present in the year 2010
1 answer:
Answer:
A(t) = 90e^0.12t ;
299 mg
Step-by-step explanation:
General Continous growth rate equation :
A = Pe^rt
A = amount present, t years after year of initial amount.
Here,
P = 90 mg, amount in year 2000
r = rate = 12% = 0.12
t = years after 2000
Therefore,
A is written as ;
A(t) = 90e^0.12t
Amount present in year 2010 ;
t = 2010 - 2000 = 10
A(10) = 90e^0.12(10)
A(10) = 90 * e^1.2
= 90 * 3.3201169
= 298.81052
= 299 mg
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