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aivan3 [116]
3 years ago
11

Solve the following quadratic equation using the quadratic formula.

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0

x=4-3i/5 x=4+3-/5

plato users!!!!

sdas [7]3 years ago
6 0
ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}

<span>5x^2-8x+5=0\to a=5;\ b=-8;\ c=5\\\\\Delta=(-8)^2-4\cdot5\cdot5=64-100=-36\\\\\sqrt\Delta=\sqrt{-36}=6i

x_1=\dfrac{-(-8)-6i}{2\cdot5}=\dfrac{8-6i}{10}=\dfrac{4-3i}{5}\\\\x_2=\dfrac{-(-8)+6i}{2\cdot5}=\dfrac{8+6i}{10}=\dfrac{4+3i}{5}
</span>
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Answer:

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Step-by-step explanation:

Usually, these are solved in 2 steps:

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Doing that, we have ...

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Another way to do these is to rewrite the proportion with both sides inverted:

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Now, all you need to do is multiply by 5.

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Or, you can do both of the original steps at the same time:

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  n = (49·5)/36 = 245/36

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