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luda_lava [24]
4 years ago
6

Type an equation for the following pattern.

Mathematics
1 answer:
monitta4 years ago
7 0
I’m pretty sure it’s Y=15 over 3 but I’m not toooo sure
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Answer:

1 1/3

Step-by-step explanation:

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Using a stopwatch, Tyrone determines it takes him 58. 2 minutes to travel 30 miles to work. The stopwatch measures to hundredths
nekit [7.7K]

The most accurate determination for the number of 45.36 feet per second Tyrone traveled on his way to work.

Given that,

Using a stopwatch Tyrone determines it takes him 58.2 minutes to travel 30 miles to work the stopwatch measures to hundredths of a minute going by the accuracy of the stopwatch.

We have to determine,

Which is the most accurate determination for the number of feet per second Tyrone traveled on his way to work?

According to the question,

Tyrone determines it takes him 58.2 minutes to travel 30 miles to work,

the stopwatch measures to hundredths of a minute going by the accuracy of the stopwatch are determined by,

\rm  Speed = \dfrac{Distance}{Time}

Substitute the values in the equation,

\rm  Speed = \dfrac{Distance}{Time}\\\\Speed = \dfrac{30}{58.2}\\\\Speed = \dfrac{50}{97}  \ miles \ per \ minute

If 1 mile = 5,280 feet, then his speed is,

\rm  Speed = \dfrac{50}{97}  \ miles \ per \ minute\\\\  Speed = \dfrac{50}{97}  \times 5280 \\\\ Speed= \dfrac{26,400}{97}\ feet \ per \ minute\\

And 1 minute = 60 seconds, then his speed is,

\rm  Speed= \dfrac{26,400}{97}\ feet \ per \ minute\\\\ Speed= \dfrac{26,400}{97} \times \dfrac{1}{60} \\\\ Speed = \dfrac{4400}{97} \ feet \ per \ second \\\\ Speed = 45.36 \ feet \ per \ second

Hence, The most accurate determination for the number of 45.36 feet per second Tyrone traveled on his way to work.

For more details about Equation refer to the link given below.

brainly.com/question/971941

6 0
3 years ago
If two angles are supplementary and one of them is 30°, what is the measurement of the second angle?
Setler79 [48]
150 degrees because supplementary angles add up to 180 degrees
6 0
4 years ago
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