. -((-55) + 2) How to solve this including step by step

Mathematics

1 answer:

skad [1K]2 years ago

7 0

Answer:

Step-by-step explanation:

apply the rule: - (a)=a

- (-55)=55

=55+2

add the numbers: 55+2=57

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How do you do this?Can you help me with the steps? I don't really get this a lot

polet [3.4K]

Before you do the steps, change the fractions given to improper fractions:
2 2/3 = 8/3
3 1/6 = 19/6

Now, I think the first step they want you to write is:
8/3 (divided by) 19/6

When you divide two fractions, it's the same as multiplying the first fraction by the reciprocal of the second fraction. (A reciprocal is a fancy way of saying you flip the fraction)
So the next step will look like this:
8/3 x 6/19

With this setup, you can cross simplify the fractions so that they look like this:
8/1 x 2/19
When you multiply this, you get 16/19
Let me know if you have any questions!

4 0

3 years ago

Read 2 more answers

Write the polynomial in factored form. <br><br> p(x)=(x+5)(x-___)(x+___)

Rom4ik [11]

Answer:

Step-by-step explanation:

Given : $p(x)=x^{3} +6x^{2} -7x-60$

Solution :

Part A:

First find the potential roots of p(x) using rational root theorem;

So, $\text{Possible roots} =\pm\frac{\text{factors of constant term}}{\text{factors of leading coefficient}}$

Since constant term = -60

Leading coefficient = 1

$\text{Possible roots} =\pm\frac{\text{factors of 60}}{\text{factors of 1}}$

$\text{Possible roots} =\pm\frac{1,2,3,4,5,6,10,12,15,20,60}{1}$

Thus the possible roots are $\pm1, \pm2, \pm 3, \pm4, \pm5,\pm6, \pm10, \pm12, \pm15, \pm20, \pm60$

Thus from the given options the correct answers are -10,-5,3,15

Now For Part B we will use synthetic division

Out of the possible roots we will use the root which gives remainder 0 in synthetic division :

Since we can see in the figure With -5 we are getting 0 remainder.

Refer the attached figure

We have completed the table and have obtained the following resulting coefficients: 1 , 1,−12,0. All the coefficients except the last one are the coefficients of the quotient, the last coefficient is the remainder.

Thus the quotient is $x^{2} +x-12$