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3 years ago

Whats the answer please tell me

Mathematics

2 answers:

Nostrana [21]3 years ago

7 0

Answer:

2 out of 10 or 2/10

Step-by-step explanation:

1 brown shoes + 7 black shoes = 8

that means there were 2 other students wearing neither so out of the 10 students 2 weren't wearing black or brown shoes making 2/10

Olenka [21]3 years ago

6 0

Answer:2 student not wearing any of the color

Step-by-step explanation:

1 student wearing brown Brown and black 1+7=8

7student wearing black

And 2 students wearing none of the above

So the answer would be 2 kids not wearing black or brown

Hope this helped

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Manny is covering a book. The front of the book is 11.2 inches high and 7.3 inches wide. What is the area of the front of the bo

irina [24]

Answer:

81.76in^2

Step-by-step explanation:

Given data

Lenght of book= 11.2 inches

WIdth of book= 7.3 inches

We know that Area= Length* Width

Area= 11.2*7.3

Area= 81.76 in^2

Hence the area of the front of the book is is 81.76in^2

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3 years ago

liq [111]

Answer:

whaaaaaa

Step-by-step explanation:

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3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

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2 years ago

Please help me with this math problem

andrey2020 [161]

Answer:

Step-by-step explanation:

How to solve your problem

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2 years ago

Which integer represents the following: –(–28)?

egoroff_w [7]

Answer:

Step-by-step explanation:

When there is a - symbol directly outside parenthesis, you always assume a 1 to be there.

-(-28) = -1(-28)

-1 × -28 = 28

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2 years ago