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den301095 [7]
3 years ago
13

A wallet contains five $10 bills, three $5 bills, six $1 bills, and no larger denominations. If bills are randomly selected one-

by-one from the wallet, what is the probability that at least two bills must be selected to obtain the first $10 bill?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

\frac{4}{21}

Step-by-step explanation:

Another way of phrasing this question is this; if only two bills are selected without replacement, what is the probability that at one of the two bills will be a $10 bill:

P(One $10 bill) = P(picking a $10 bill first then another type) + (picking another

                            type then a $10 bill)

                        = \frac{5}{15}*\frac{10}{14}+\frac{10}{15} *\frac{5}{14} = \frac{4}{21}

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Step-by-step explanation:

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I wi mark you brainless and give point of this gets completed
Paraphin [41]

Answer:

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2. (x - 7)( x - 8)

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Step-by-step explanation:

I'm so sorry it took this long that made my brain hurt it was worth it

Sorry it took so long..

hope I helped!!

5 0
3 years ago
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11Alexandr11 [23.1K]
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I hope this helps! I'm hoping google translated your question properly, I'm native english speaking
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2 years ago
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