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den301095 [7]
3 years ago
13

A wallet contains five $10 bills, three $5 bills, six $1 bills, and no larger denominations. If bills are randomly selected one-

by-one from the wallet, what is the probability that at least two bills must be selected to obtain the first $10 bill?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

\frac{4}{21}

Step-by-step explanation:

Another way of phrasing this question is this; if only two bills are selected without replacement, what is the probability that at one of the two bills will be a $10 bill:

P(One $10 bill) = P(picking a $10 bill first then another type) + (picking another

                            type then a $10 bill)

                        = \frac{5}{15}*\frac{10}{14}+\frac{10}{15} *\frac{5}{14} = \frac{4}{21}

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Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.
tekilochka [14]

Answer:

-\frac{3}{4}

Step-by-step explanation:

the equation for finding the slope of a line when given two points is \frac{y_2-y_1}{x_2-x_1}, aka the change in y over the change in x.

pick one of your coordinate pairs to be y_2\\ and x_2. it doesn't matter which coordinate pair you choose as long as you keep them as y_2\\ and x_2. the remaining coordinate pair will be y_1 and x_1.

for this example, i'll use (2, 10) for y_2\\ and x_2 and (6, 7) for y_1 and x_1.

<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em>y_2\\ and 2 for x_2<em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>

<em />

first, start by plugging in the y-value from the coordinate pair of your choosing in for y_2\\. since i chose (2, 10) for y_2\\ and x_2, i'll plug in 10 for y_2\\.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-y_1}{x_2-x_1}

then plug in the remaining coordinate pair's y-value in for y_1. since the coordinate pair that's left is (6, 7), i will plug in 7 for y_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{x_2-x_1}

now i'm going to plug in the x-values. i chose (2, 10) to plug in for y_2\\ and x_2, so now i'll plug in 2 for x_2.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-x_1}

and all that's left to plug in is the x-value from (6, 7), so i will plug that in for x_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-6}

after plugging in all the values, you have \frac{10-7}{2-6}.

subtract 10 - 7 as well as 2 - 6.

\frac{10-7}{2-6} ⇒ \frac{3}{-4}

\frac{3}{-4} cannot be simplified, therefore the slope of the line is \frac{3}{-4} or -\frac{3}{4}.

i hope this helps! have a lovely day <3

7 0
2 years ago
The ratio of red cars to blue cars in a parking lot was 8 : 7. If there were 48 red cars, how many blue cars were there?
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What you need to do is multiply both sides by the same number. If 8 times 6 is 48, then 7 times 6 is your answer.
8 0
3 years ago
PLEASE HELP THIS IS MATH 171 the topic is partial fraction decomposition
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What do you mean? Where is the question?

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You will get 57.44’$
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3 years ago
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suter [353]
I think the greatest number less than 700 with 9 in the tens place and different digits in each of the other places is 698.
I chose 6 to be in the one of hundreds place because it is the greatest number that is less than 7 in the hundreds place. I also chose 8 to be in the ones place because it is different from 6 and 9 and the greatest number in the ones place that is not 9.
8 0
2 years ago
Read 2 more answers
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