(12,24)
Hope it helps love.
-Joker7721
Step-by-step explanation:
5(a-3)(a-3)
5(a-3)^2
X^4(2x+1) - (2x+1)
(x^4-1)(2x+1)
(x^2-1)(x^2+1)(2x+1)
(x-1)(x-1)(x^2+1)(2x+1)
Answer:
Step-by-step explanation:
(1) 2x - 6y = -12
(2) x + 2y = 14
There is a -6y and a +2y. Since they have opposite signs, I'll try to eliminate the y terms. (That's my choice. There is more than one way to solve these.)
Multiply eq. (2) by 3:
3x + 6y = 42
Then add the result to eq. (1) to eliminate the y terms:
2x - 6y = -12
3x + 6y = 42
------------------
5x = 30, so x = 6
Now plug the value of x into eq. (2) and solve for y:
6 + 2y = 14
2y = 8
y = 4
Why did I use eq. (2) to solve for y? Because it's less work. I could have used eq. (1) instead:
2(6) - 6y = -12
12 - 6y = -12
-6y = -24
y = 4
More than one way to solve.
Whats the topic that you want me to tell about
