What is the next term of the arithmetic sequence? 6,2, -2, -6,

Can someone please help me with this

vaieri [72.5K]

Answer:4 in each package

Step-by-step explanation:

3 0

2 years ago

The diagram shows a triangle. 2x 60° 2x What is the value of x? Х=

FinnZ [79.3K]

2x+2x+60=180 because the angles have to add up to 180

So you have

4x+60=180

4x=120

x=30

3 0

2 years ago

Read 2 more answers

Yo what's 0.994 rounded to the nearest tenth

krek1111 [17]

Answer:To round 0.994 to the nearest tenth consider the hundredths’ value of 0.994, which is 9 and equal or more than 5. Therefore, the tenths value of 0.994 increases by 1 to 0.

0.994 rounded to the nearest tenth = 1.0

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

Researchers measured the percent body fat and the preferred amount of salt (percent weight/volume) for several children. Here ar

Anon25 [30]

Answer: b) τ = 0.3

Step-by-step explanation:

Given the data :

Amount of salt (x)____% body fat(y)

0.2 _______________20

0.3 _______________30

0.4 _______________22

0.5 _______________30

0.7 _______________38

0.9 _______________23

1.1 ________________30

The correlation Coefficient as obtained from the online pearson correlation Coefficient calculator is 0.3281 = 0.3 (to one decimal place) which implies that a weak positive correlation or relationship exists between the preferred amount of salt taken to the percentage body weight of an individual. This is because the value is positive and closer to 0 than 1. The closer the weaker the degree of correlation. With positive values implying a positive relationship (that is an increase in variable A leads to a corresponding increase in B and vice-versa).

4 0

3 years ago