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Katarina [22]
3 years ago
10

If (5,3) is a point on the graph of y = f(x), which of the following must be on the graph of y= -8f(x)?

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

the new points that must be found in the graph is (5, -24).

The given points;

(5, 3)

function, y = f(x)

To determine the new points that will be on y = -8f(x)

The points that will be found on this graph must be within the given range of the function.

These new points are calculated as follow;

the x-intercept must remain the same while the y-intercept changes.

The y-value is already given as 3 and we rewrite it as;

f(5) = 3

-8f(5) = -8(3) = -24

The new coordinate that will be on the line = (5, - 24)

Thus, the new points that must be found in the graph is (5, -24).

Learn more here: brainly.com/question/7666399

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An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
Y-3=-3y-43 how would i solve?​
frez [133]

Answer: y−3=−3y−43

Step 1: Add 3y to both sides.

y−3+3y=−3y−43+3y

4y−3=−43

Step 2: Add 3 to both sides.

4y−3+3=−43+3

4y=−40

Step 3: Divide both sides by 4.

4y

4

=

−40

4

y=−10

Answer:

y=−10

Step-by-step explanation: brainliest:)

7 0
3 years ago
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